Skip to main content

A Different Way to Memorize the Taylor Series and a Cry For Mathematical Help

A Different Way to Memorize the Taylor Series and a Cry For Mathematical Help

As an undergrad, and throughout my graduate career until now, I've always had a hard time remembering how to apply a Taylor series.  I knew there were coefficients in front of powers of x and that those coefficients somehow involved derivatives of the function I was trying to aproximate with the Taylor series, but that was aobut it.  Even when I looked up the formula, there was still always some initial confusion.  I'd arrive at an equation that looked like the following


followed by a little bit of text blithely informing that if I'd only take the nth derivative of both sides of the equation, and evaluate the derivative at x = b, then of course I'd see that the coefficient a sub n could be written as


This inevitably led to having to remember that the first n-1 terms in the sum would become zero after they were differentiated n times, and that the terms of n+1 and above would become zero when x was equal to b so that only the term containing a sub n was left.  Perhaps I'm a bit slow, but that was my process every single time.

Looking at the formulas last night for the umpteenth time, it occurred to me that the first two terms in the Taylor series are how we approximate functions when we only want to add a small change in x.  We get the value for the function at x equals b, then approximate the function as a straight line and multiply the slope of that line times a small change in x to get the approximate value of the function at the location b plus our small change in x

In other words, we as the question, how does our function change for a small change in x, (what's it's slope with respect to x?), and then multiply that slope by our small change in x to get the associated small change in the function.

Now, look at a Taylor series with three terms:


The second term is the slope with respect to x I just mentioned.  If we write the second derivative in a different notation, we have


which, when I squint at it in just the right light looks for all the world like the amount my function will change for a small change in x squared.  An then with a second look, I see that the derivative is in fact multiplied by x squared.  It's slightly more visible if we take b equal to zero, and rewrite the series as:


This looks kind of great!  A Taylor series is just a series of corrections that ask what's the slope of my function with respect to a power of x and then multiplies that slope by the particular power of x.  That's far easier for me to remember, but there's still one issue left.  What about the annoying factors of one over n factorial out in front of each term?

And, that brings me to my second mathematical sin for the day, or more politely worded, my second opportunity to be mathematically clarified. I'm calling it the inverse chain rule.  The chain rule provides a way to take the derivatives of composite functions like 


by first taking the derivative of the outer function, (cosine in this case), with respect to its argument, (x squared in this case), then determining how the argument changes with respect to x and finally determining the entire change with respect to x by multiplying the two changes together. So, using the chain rule, I can ask the question: how does my function of x squared change with respect to x?

A Little Formal Math Help Please?
In my above reasoning, I've asked the inverse of the chain rule question.  I'm asking, (for the third term), how my function of x varies with respect to x squared.  The terms of n factorial are just one over the nth derivative of the power of x I'm interested in



Since I've asked the inverse of the chain rule question question, I'm guessing that instead of multiplying [the derivative of the my function with respect to x to the n] by [the derivative of x to the n with respect to x] that multiplying by the inverse of [the derivative of x to the n with respect to x].  I know this is correct because it gives the correct terms for a Taylor series, but I don't know how to say it formally or explain it completely.  Would anyone like to clarify... please?

Summary of the Method
So, at the end of the day, the way I will now always remember the Taylor series is as a set of patches in powers of x to an approximtaion.  I multiply each power of x by the slope of the function with respect to that power of x.  To take care of the inverse chain rule, if the power is n, I then divide by the nth derivative of the nth power of x, (also known as n factorial).

Picture of the Day:
From 1/27/13


Comments

Popular posts from this blog

More Cowbell! Record Production using Google Forms and Charts

First, the what : This article shows how to embed a new Google Form into any web page. To demonstrate ths, a chart and form that allow blog readers to control the recording levels of each instrument in Blue Oyster Cult's "(Don't Fear) The Reaper" is used. HTML code from the Google version of the form included on this page is shown and the parts that need to be modified are highlighted. Next, the why : Google recently released an e-mail form feature that allows users of Google Documents to create an e-mail a form that automatically places each user's input into an associated spreadsheet. As it turns out, with a little bit of work, the forms that are created by Google Docs can be embedded into any web page. Now, The Goods: Click on the instrument you want turned up, click the submit button and then refresh the page. Through the magic of Google Forms as soon as you click on submit and refresh this web page, the data chart will update immediately. Turn up the:

Cool Math Tricks: Deriving the Divergence, (Del or Nabla) into New (Cylindrical) Coordinate Systems

Now available as a Kindle ebook for 99 cents ! Get a spiffy ebook, and fund more physics The following is a pretty lengthy procedure, but converting the divergence, (nabla, del) operator between coordinate systems comes up pretty often. While there are tables for converting between common coordinate systems , there seem to be fewer explanations of the procedure for deriving the conversion, so here goes! What do we actually want? To convert the Cartesian nabla to the nabla for another coordinate system, say… cylindrical coordinates. What we’ll need: 1. The Cartesian Nabla: 2. A set of equations relating the Cartesian coordinates to cylindrical coordinates: 3. A set of equations relating the Cartesian basis vectors to the basis vectors of the new coordinate system: How to do it: Use the chain rule for differentiation to convert the derivatives with respect to the Cartesian variables to derivatives with respect to the cylindrical variables. The chain

The Valentine's Day Magnetic Monopole

There's an assymetry to the form of the two Maxwell's equations shown in picture 1.  While the divergence of the electric field is proportional to the electric charge density at a given point, the divergence of the magnetic field is equal to zero.  This is typically explained in the following way.  While we know that electrons, the fundamental electric charge carriers exist, evidence seems to indicate that magnetic monopoles, the particles that would carry magnetic 'charge', either don't exist, or, the energies required to create them are so high that they are exceedingly rare.  That doesn't stop us from looking for them though! Keeping with the theme of Fairbank[1] and his academic progeny over the semester break, today's post is about the discovery of a magnetic monopole candidate event by one of the Fairbank's graduate students, Blas Cabrera[2].  Cabrera was utilizing a loop type of magnetic monopole detector.  Its operation is in concept very sim