Groups and Their Graphs: Clarifications of Normal Subgroup Theorem and Test for Normal Subgroup Elements

“the set K that contains all elements of G such that...” becomes
“the set K containing every element of the group G such that...”
The following paragraph that contained the test was easier for me to understand with the following substitution:
“If f maps all elements onto I...” becomes
“If f maps all elements of G onto I...”
Hope this helps! Any comments or questions?
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