tag:blogger.com,1999:blog-2269351477810212131.post4355649550625314012..comments2024-03-22T08:22:47.170-07:00Comments on Copasetic Flow: It’s Obvious. Not! A Few Answers and More Questionsantigrav_kids KD0FNRhttp://www.blogger.com/profile/08273077706643157078noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-2269351477810212131.post-67116302538549789082008-08-24T16:58:00.000-07:002008-08-24T16:58:00.000-07:00Thanks!Your explanations cleared up everything! On...Thanks!<BR/><BR/>Your explanations cleared up everything! Once the reader is aware of the technique you mentioned in your first answer, then it becomes common-place to look for it.<BR/><BR/>Thanks for the correction on the third question and the confirmation that there isn't a typo.antigrav_kids KD0FNRhttps://www.blogger.com/profile/08273077706643157078noreply@blogger.comtag:blogger.com,1999:blog-2269351477810212131.post-41883172444153120452008-08-24T16:41:00.000-07:002008-08-24T16:41:00.000-07:001) It's a fairly standard thing to do in different...1) It's a fairly standard thing to do in differential equations...you multiply the whole thing by something that reduces the LHS to a recognisable derivative via product rule.<BR/><BR/>2. Yes. It's often known as product rule. You wrote it out yourself.<BR/><BR/>3. No. You missed a point here. The LHS is integrating with respect to velocity squared. When x = x0, v^2 = v0^2, making that the upper limit (and the value of the LHS (+C))<BR/><BR/>Hope I helped.Anonymousnoreply@blogger.com